At a wall the velocity is zero. However, it is more effective to calculate the stress at the wall directly. The mass conservation amounts to
\frac{\partial \rho }{\partial t} + \rho ,_{j} v_j + \rho v_{j,j}=0. | (612) |
For stationary flow ( \partial \rho / \partial t =0) at the wall ( \boldsymbol{v}=0) we arrive at
v_{j,j}=0 | (613) |
\frac{\partial v_n}{\partial n} + \frac{\partial v_t}{\partial t} = 0. | (614) |
\frac{\partial v_n}{\partial n} = 0. | (615) |
Now, because
t_{nn}=2 \mu^T v_{n,n} - \frac{2}{3} (\mu^T v_{k,k} + \rho k) | (616) |
one obtaines t_{nn}=0, since v_{k,k}=0 (just derived) and also the turbulent kinetic energy at the wall is zero. For the tangential component one obtains:
t_{nt} = \mu^T (v_{n,t}+v_{t,n}). | (617) |
Since v_{n,t}=0, one arrives at
The velocity at P (Figure ) is now decomposed into a component normal and a component tangent to the wall:
(\boldsymbol{v}_P)_n = (\boldsymbol{v}_P \cdot \boldsymbol{e}_n) \boldsymbol{e}_n | (619) |
and
(\boldsymbol{v}_P)_t = \boldsymbol{v}_P - (\boldsymbol{v}_P \cdot \boldsymbol{e}_n) \boldsymbol{e}_n =\boldsymbol{v}_P - (\boldsymbol{v}_P \cdot \boldsymbol{n}) \boldsymbol{n} = (\boldsymbol{v}_P \cdot \boldsymbol{e}_t) \boldsymbol{e}_t , | (620) |
where \boldsymbol{e}_n and \boldsymbol{e}_t are unit vectors in n- and t-direction, respectively. The stress tensor amounts to:
\begin{bmatrix} 0 & t_{nt} \\t_{nt} & t_{tt} \end{bmatrix} | (621) |
and the normal vector orthogonal and external to the surface satisfies:
\boldsymbol{n}= - \boldsymbol{e}_n + 0 \cdot \boldsymbol{e}_t. | (622) |
This leads to the following stress vector \boldsymbol{t} :
\begin{bmatrix} 0 & t_{nt} \\t_{nt} & t_{tt} \end{bmatrix} \cdot \begin{bmatrix} -1 \\0 \end{bmatrix} = \begin{bmatrix} 0 \\-t_{nt} \end{bmatrix} | (623) |
or
Approximating v_{t,n} by
v_{t,n} \approx \frac{\boldsymbol{v}_t \cdot \boldsymbol{e}_t }{(\boldsymbol{r}_S - \boldsymbol{r}_P) \cdot \boldsymbol{n} }, | (625) |
one obtains by combining Equations () and ():
\boldsymbol{t}= \frac{-\mu^T \boldsymbol{v}_t \cdot \boldsymbol{e}_t }{(\boldsymbol{r}_S - \boldsymbol{r}_P) \cdot \boldsymbol{n}} \cdot \boldsymbol{e}_t = - \frac{\mu^T [\boldsymbol{v}_P - ( \boldsymbol{v}_P \cdot \boldsymbol{n}) \boldsymbol{n}] }{(\boldsymbol{r}_S - \boldsymbol{r}_P) \cdot \boldsymbol{n}}. | (626) |
Therefore, the integral at the wall can be approximated by:
\left ( \int_{\text{wall}}^{} t_{ij} n_j da \right ) \boldsymbol{e}_i \approx - \frac{\mu^{T(m-1)} A_w}{(\boldsymbol{r}_S - \boldsymbol{r}_P) \cdot \boldsymbol{n}} \boldsymbol{v}_P^{(m)} + \mu^{T(m-1)} A_w \frac{(\boldsymbol{v}_P^{(m-1)} \cdot \boldsymbol{n}) \boldsymbol{n}}{(\boldsymbol{r}_S - \boldsymbol{r}_P) \cdot \boldsymbol{n}}, | (627) |
where A_w is the area of the wall face. The first term contributes to the left hand side, the second term to the right hand side of the system of equations.